In an oscillating LC circuit, L=25 mH and C=7.8 x10^-6 F. At time t=0 the current is 9.2 mA, the charge on the capacitor is 3.8 x 10^-6 C, and the capacitor is charging. What is the total energy in the circuit?
I know I just need to do Ub+Ue=U, but here is my question. Are L and C constant...
I really struggle with these and would just like someones input on how to best solve these, I can never seem to cancel everything out except the variable I am looking for. I have:
E-i1-Ri2=0
Ri2-Ri3=0
i1+i2+i3
I am looking to solve for i1
All R's are equal to 0.73 x10^6 ohms so I just...
We worked out this problem in class and I'm still confused:
A wire of resistance 5 ohms is connected to a battery whose emf is 2.0 V and whose internal resistance is 1 ohm. In 120 seconds, how much energy is (a) transferred from chemical form in the battery, (b) dissipated as thermal energy in...
A coaxial cable used in a transmission line has an inner radius of 0.10 mm and an outer radius of 0.60 mm. Calculate the capacitance per meter for the cable. Assume that the space between the conductors is filled with polystyrene. Kappa for polystyrene is 2.6
I have no clue how to start or...
Homework Statement
So this is just a general question. If I have multiple capacitors, how can I determine the number of electrons at a certain point along the circuit. I know q=ne so I just really need q but that's the biggie. I also know q=CV. So to figure out q at any point, what do I...
Two large parallel copper plates are .05 meters apart and have a uniform electric field between them. An electron is released from the negative plate at the same time that a proton is released fro the positive plate. Neglect the force of the particles on each other and find their distance from...
In Milikan's experiment, an oil drop of radius 1.64x10^-6 m and density of 0.851 g/cm^3 is suspended in a chamber where the downward electric field of 1.92x10^5 N/C is applied. Find the charge on the on drop.
I know that F=qE, but the drop is suspended so it can't really a force because it...