Recent content by Sprinkle159

Hey, this might help. "Chemical engineers are expected to have an employment decline of 2 percent over the projections decade. "(http://www.bls.gov/oco/ocos027.htm) This -2% growth rate might go a little way in explaining the lack of current popularity. Note: civil is projected to grow by 24%...

Not sure if this helps you, but it it helped me a little. (I'm right where you are in the work and kinetic energy chapter) "...and because the objects do not behave as particles, it is generally not correct to apply the particle form of the work-energy theorem to objects subject to frictional...

If the initial velocities of 2 particles are given, and the masses are equal, then is there some limit on what the final velocities can be? m1v1i+m2v2i=m1v1F+m2v2F (initial velocity of particle 2 is zero; v2i=0) v1i=v1F+v2F To clarify my question if particle 1 has an initial velocity...

Oh no I just had x and z there to represent equations. I should have explained that the problem description says: "concept: differential equations; using initial values to find exact solutions" So I went to the section in my calculus book talking about first order linear differential equations...

On second though: e^(integral of x)=(e^(x)+e^(-x))/2 integral(x)= ln(e^(x)+e^(-x))/2) x=(derivative) ln(e^(x)+e^(-x))/2) using chain rule gives: (2/(e^(x)-e^(-x)) * (2/(e^(x)-e^(-x))= 4/((e^(x)-e^(-x))^2) does this seem reasonable?

Thank you for the reply you were correct about it being (e^(at)-1)/(e^(at)+1), which looks much more like an equation that takes into account air resistance. I still have a couple questions though. Problem can be found here: ****(PLEASE remove the spaces between h t t p)**** h t t...

Homework Statement Problem asks what 'A' and 'a' represent,(which I think represent air resistance and acceleration), and also asks if this equation accurately describes the descent of a falling object taking air resistance into account. The question can be found here: http ://edisk. fandm...