Momentum:difference in final velocities

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SUMMARY

The discussion focuses on the final velocities of two particles during a collision, given their initial velocities and equal masses. The conservation of momentum equation, m1v1i + m2v2i = m1v1F + m2v2F, is applied, with specific values indicating that if particle 1 has an initial velocity of 50 m/s and particle 2 is initially at rest, the final velocities must adhere to conservation of energy principles. The extreme outcomes include a perfectly elastic collision where particle 1 stops and particle 2 moves at 50 m/s, and a perfectly inelastic collision where both particles move together at 0.25 m/s. Thus, final velocities are limited by these conservation laws.

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Sprinkle159
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If the initial velocities of 2 particles are given, and the masses are equal, then is there some limit on what the final velocities can be?

m1v1i+m2v2i=m1v1F+m2v2F

(initial velocity of particle 2 is zero; v2i=0)

v1i=v1F+v2F

To clarify my question if particle 1 has an initial velocity of 50 m/s, then this equation says the final velocity of particle 1 could be -550 m/s, and then the final velocity of particle 2 would be 600 m/s, which are much larger then the initial velocity of particle 1. So is there some limit on what values the final velocities can have?
 
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Yes. The collision would also need to satisfy conservation of energy.
 
... and that means that (in your example, where the masses are equal and particle 2 is initially at rest with the reference frame), there are two extreme possibilities [particle 1 stops and particle 2 takes particle's 1 initial velocity (perfectly elastic collision) and both particles stick to each other and move with velocity = 0.25 m/s (perfectly inelastic collision)] and a range between them but not beyond.
 

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