Sorry Simon I meant to say mgcos(15) is equal to the normal force, its on my diagram.
AdityaDev, I have the force along the incline as mgsin(15). I think what's really confusing me is that 37 degree angle where is it? "rope inclined at 37 degrees to the horizontal," to me says that there is a...
Homework Statement
A child pulls a 10lb sled up a 15 degree incline at a constant speed. The child is pulling on a rope attached to the sled. If the rope is inclined at 37 degrees to the horizontal and there is an 8 pound tension in the rope, what is the coefficient of friction?Homework...