I checked back to my original approach and realised it was correct, just far more difficult to work with the algebra for it as I literally just chucked it in mathaway algebra solver to get the same h=2.22m. Thank you very much to all of you for your perspectives. This question was frankly...
yeah I know I solved it already. I took a step back and realised oh, I am already given t1 = 2t2 and then just went from there, even simpler than the fraction substitution. Thank you all for your patience
Final answer h = 2.22...m
Wait I am goated, h = 2.22 metres?
I was analyzing my approach versus you guys and I finally realized where I made it hard for myself, I did not exploit symmetry, which I know IPhO problems love
Then I realized that with system of 3 equations I get overwhelmed pretty damn easily and made it...
So they reach the same h height point where the bouncing ball reaches it twice, once before and once after.
And, considering their horizontal velocities, one ball reaches it in half the time as opposed to the bouncing one *after* it bounces. But how can I relate this to height?
Rahh but I love plugging and chugging 😭😭😭
Anyways, I will start anew tomorrow with new founded wisdom, I think I know how to do this now. Let me also try not to plug and chug and see if it helps me out
Edit: Very sorry for the late reply, this week drained me but I was actively reading all of your comments
Thank you all for your replies
After using your retrospective questions and hints, and a lot of algebra I still had to muster through...
I got the height as h = 2.5m roughly. Is this...
Wild question. Even Chat GPT struggling.
What I first attempted was to find the velocity by which the projectile with v1 falls down to the ground with. This part was easy.
Kinetic energy gained = gravitational potential energy lost
Let's define our coordinate frame as up vectors being positive...