Recent content by Steelers72

I'm not sure. My answer was marked incorrect which is strange. I understand the problem and how to do it. I figured maybe my work was wrong or a small error?

I am aware, that is why I wrote my work in the 3rd step of the post. I used my own velocity range.

1. Question The speed of an electron is known to be between 6.0×10^6 m/s and 6.7×10^6 m/s . Estimate the uncertainty in its position. Homework Equations ΔpΔx ≥ h/2π (mΔv) Δx ≥ h/2π (Since Δp= mΔv) Δx≥ h/2π(mΔv) h= 6.63*10-34 J*s c= 3.0*108 mass of electron= 9.11*10-31 The Attempt at a...

I am doing a lab experiment with regard to combined circuits, and I wanted to check my data to see if I made an error in my experiment. Theoretically speaking, in a combined circuit, should Itotal (total current) be equivalent to the Imeasured value? I calculated my Itotal to be .0292A since...

Thanks for the advice. I wish there was a manual it is all written in paragraph form. Annoying.

Im not sure. It was a lab. Very frustrating because current is mentioned anywhere

I have voltage, diameter, area, and inverse area data values. How could I calculate the resistance and resistivity with these numbers? I am pretty sure resistance is R=V/I and resistivity= RA/L , so I am not sure how I can calculate resistance without an I value.

Homework Statement Six forces, each of magnitude either F or 2F, are applied to a door as seen from above in the figure. Rank in order, from smallest to largest, the six torques τ1to τ6 about the hinge. Homework Equations torque=RFsintheta The Attempt at a Solution τ1 = F*L/2 τ2 = 2F*L/4 τ3 =...

5.67pi ...i don't understand why I keep getting a wrong answer from my calculator. Thanks. So 5.67 (5.67^2)/.400 =80.37 sqrt( (80.37^2)+(.361^2) ) =80.37 ? this ok now?

so .902revs/s^2 *2piradians/rev=1.80pi radians/s^2 (1.80^2)/.400 =8.1 sqrt( (8.1^2)+(.361^2) ) =8.11 Is this correct?

So I have to convert 1.11 revolutions to radians? so would it be 1.11 rev*2piradians/rev ?

Based on my original post, which step did I mess up centripetal acceleration = (v*v)/r I calculated v (tangential velocity) to be 1.11 ---which is correct based on answer key = (1.11^2)/.400 =3.08

What would be the magnitude though? I am confused as to why my answer of -8.38 radians/s^2 is wrong

α = −8 radians/s2 ANSWER 2: Deduction: -3% α = −8π3 radians/s2 The question only asks for the magnitude of the angular acceleration. ANSWER 3: Deduction: -3% α = −8.4 radians/s2 The question only asks for the magnitude of the angular acceleration. ANSWER 4: Deduction: -3% α = −2.67π...

-8.0 didnt work as well.