Thanks for the replies.
Is that because at release the positions of the observer and the rock coincide and since the spacetime is tangentially flat, the formula applies as in special relativity?
So is it true that if the rock's position was different from the observer's, the formula wouldn't...
If a stationary observer throws a rock out in the radial direction in a Schwarzschild geometry, what is the relationship between the energy of the rock and its speed in the observer's frame?
I'm a bit confused because the book seems to say it's E = \frac{m}{\sqrt{1-V^2}}, but I thought that...