- #1
stephenmitten
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If a stationary observer throws a rock out in the radial direction in a Schwarzschild geometry, what is the relationship between the energy of the rock and its speed in the observer's frame?
I'm a bit confused because the book seems to say it's [tex]E = \frac{m}{\sqrt{1-V^2}}[/tex], but I thought that only applied to inertial frames in special relativity.
Thanks.
I'm a bit confused because the book seems to say it's [tex]E = \frac{m}{\sqrt{1-V^2}}[/tex], but I thought that only applied to inertial frames in special relativity.
Thanks.