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  1. S

    Triac - Power dissipated in light bulb

    Much appreciated Gneil, V/I = R 230/0.43 = 534.884, Calculate I for new Voltage: V/R = I 206/534.884 = 0.386 Power Dissipated = 206 * 0.386 = 79.5 W Is this correct?
  2. S

    Triac - Power dissipated in light bulb

    Homework Statement A triac is used in a dimmer switch to control a 100W light bulb. If the firing angle is set for α=∏/3 estimate the power dissipated in the bulb Rated at 100W and the voltage source 230V @ 50Hz. Homework Equations Vpeak = Vrms/0.707 The Attempt at a Solution...
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