Recent content by Strawer

Experience tells me that if I would give m1 a push the rope would go slack. Or is that because i accelerate it? Also wouldn't the rope go slack if v1 > v2 because s=vt and if the rope is taut then s1=s2? Anyways, new try ƩF=ma The relevant forces acting on m2 is friction...

Homework Statement Two blocks with equal masses m1=m2=5kg are connected via a pulley, as shown. Take \mu = 0.25. Find the acceleration given that a) m1 is moving down, b)m1 is moving up. If m2=6 kg for what values of m1 will the pair move att constant speed? Homework Equations F=ma...

Anyone? According to the answer sheet the correct answer should be 0.67 m/s^2 but I'm starting to wonder whether that's true or not?

Here's the figure btw.

Homework Statement A child pulls a 3.6 kg sled at 25 degrees to a slope that is 15 degrees to the horizontal, as in the figure. The sled moves at a constant velocity when the tension is 16 N. What is the acceleration of the sled if the rope is released? Homework Equations F=ma...

There isn't a z coordinate for rA but as I understand that doesn't matter anyways since the electric field has no component in the z direction.

Hehe well it's good to know that I'm not the only one who struggles with stuff like that :smile:

Oh I see now. My homework would be a lot loss painful if I could avoid stuff like this but it doesn't matter how thorough I am, I often miss things anyways. I think I might have a mild form of dyscalculia or something.. But thank you for your assistance!

Well i have noticed that I'm very prone to making rudimentary mistakes often but I don't believe that to be the case here. When calculating the integral I do as follows: - \left[ x^2 \right]_{1}^{2} - \left[ -y^3 \right]_{-2}^{1} = -(4-1) - (-1+8)= -3 - 7 = -10 V

Homework Statement An electric field is given by E = 2xi-3y2j N/C. Find the change in potential from the position rA = i - 2j m to rB = 2i + i + 3k m. Homework Equations VB - VA = -\int_A^B E\cdotds The Attempt at a Solution ΔV= -\int_1^22x dx - \int-3y^2 dy The second...