Recent content by stungheld

yeah, that's it. Just r there. Now its correct ##5r - 2 = 2r^2 ##

True but didnt make much difference. i now get ##5r - 2 = 2r^3 ## Cant find any mistakes but there must be some.

Homework Statement The sum of first three numbers of the arithmetic sequence is 54. If you subtract 3 from the first one, leave the second one unchanged and add 12 to the third one you get the first three numbers of the geometric sequence of the form ##ar + ar^2 + ar^3 + ... ar^n ## Find r...

If q = 0 p = -1 and for the last one its p = -2 and q = 1 5 solutions would then be the answer

How did i count p and q to be 0 twice? I counted both to be 0, two cases were in the first q is 0 and p p1 or p2 ( making the first expression 0) and the only case were p and q are non zero but still make zero are p = q = 1. I see no other way

p and q = 0 q = 0 and p either of two solutions p = 0 and q = -1 p = q = 1 That makes it 5. Is that it?

That seems more complicated. Any chance we could try resolving this polynomial division? How to check the solutions after the last part of the division? I separated the cases in the x(-p^3 - p^2 + 2pq) + (-qp^2 - qp + q^2 + q) = 0. I tried to eliminate one variable by substituting p for q but...

Well i get x(-p^3 - p^2 + 2pq) + (-qp^2 - qp + q^2 + q) = 0 So like you said A and B are 0. I set them to 0 and solved for p but got some cubic equation so i supposed three solutions there. But i can't solve for q.

(p^2 + p - q)(- px - q) + q(px + 1)= 0 This must be true for some p and q so that there is no remainder. But how do i find those values? There are three variables here.

I don't see it

I haven't done long division before so i checked it out online and tried to do it.Could you check this?

It is true what you said. I added = 0. It shouldn't be there. I don't seem to have any idea on how to start, maybe you could help me with some subtle hint without giving me the step?

Homework Statement How many pairs of solutions make x^4 + px^2 + q = 0 divisable by x^2 + px + q = 0 Homework Equations x1 + x2 = -p x1*x2= q[/B] The Attempt at a Solution I tried making z = x^2 and replacing but got nowhere. I figure 0,1,-1 are 3 numbers that fit but I am not sure what's...