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In that case... height = (v^2) / (2g) height = (12m/s)^2 / (2*9.8m/s^2) height = 144m^2/s^2 / 19.6m/s^2 height = 7.35m or if I used energy... KE=GPE 0.5mv^2 = mgh 0.5v^2 = gh (mass drops out) 0.5*(12m/s)^2 = h*9.8m/s^2 72m^2/s^2 = h*9.8m/s^2 (72m^2/s^2) / (9.8m/s^2) = 7.35m...

Homework Statement At the base of a frictionless icy hill that rises at 28.0 degrees above the horizontal, a toboggan has a speed of 12.0m/s toward the hill. How high vertically above the base will it go before stopping? Homework Equations height = [(v*sin (angle))^2] / (2g) The...