Recent content by sun

Things aren't that obvious to me :(. I came to the realization that 1kW=3.6x10^6J, so 6kW=2.16x10^7J.

I know its a bit tedious, but any suggestions?

Homework Statement A particular engine has a power output of 6.00 kW and an efficiency of 26.0%. Assume the engine expels 6000 J of energy in each cycle. (a) Find the energy absorbed in each cycle. (b) Find the time required to complete each cycle. P=W/delta t e=W/Q...

Homework Statement A gas is taken through the cyclic process described by Figure P12.16. http://www.webassign.net/sf/p12_16.gif (a) Find the net energy transferred to the system by heat during one complete cycle. (b) If the cycle is reversed -- that is, the process follows the path ACBA --...

Heat absorbance: PLS PLS HELP ASAP! Homework Statement A quantity of a monatomic ideal gas undergoes a process in which its pressure is increased by a factor of n = 3 and its volume is increased by a factor of m = 6 as shown in Figure P12.12. What is the heat absorbed by the gas during this...

YES! Thank you ! I got it :) <3

do i divide 1.47*10^5 by 6, b/c there are 6 sides to the cube?

this is what I've done: P(.027m^3)=(3mol)(8.31J/mol*K)(296K) P=2.73*10^5 F=2.73*10^5(.54)=1.47*10^55 N, but that is incorrect. any idea as to what i may be doing wrong. And thank you for your help.

argg still lost and confused

I figured it out: KE=1/2(mv^2) KE=3801.83 m=20.2*10^-3

any suggestions. I would love the help and greatly appreciate it. :)

I also tried PV=NkT would N equal 3*(6.02*10^23)? If so, what i did was P(.027m^3)=1.81*10^24(1.381*10^-23)(296) i got 2.74*10^5 Then i multiplied that by the area .54 and got 1.47*10^5N, but that's wrong.

I'm not sure how to calculate the moles. I tried V(f)/V(i)=n(f)T(f)/n(i)T(i) when i solved for n(i) i got .0011mol. But i guess that isn't correct.

any help would be appreciated :)

1.21E7Pa (.1m^3)=1.36E5Pa (V)=629 ballooons thank you