How Is Net Energy Transferred in a Cyclic Thermodynamic Process?

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SUMMARY

The net energy transferred to the system by heat during one complete cycle of the cyclic thermodynamic process is calculated by summing the heat values (Q) for each segment of the cycle. In this case, the correct total is 40,000 J, which includes contributions from segments A to B, B to C, and C to A. When the cycle is reversed (path ACBA), the net energy transferred by heat must be recalculated based on the new path, which will yield a different total. Accurate application of the first law of thermodynamics is essential for these calculations.

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Homework Statement



A gas is taken through the cyclic process described by Figure P12.16.

http://www.webassign.net/sf/p12_16.gif

(a) Find the net energy transferred to the system by heat during one complete cycle.

(b) If the cycle is reversed -- that is, the process follows the path ACBA -- what is the net energy transferred by heat per cycle?

PV=[nR]T
[nR]=PV/T
W=-P(deltaV)What I have done so far:______P(kPa)--------V(m^3)------------U(J)--------------[nR]
A_____2x10^3--------- 6 --------------18x10^3 ----------43.96
B_____8x10^3----------10-------------120x10^3---------293.04
C_____2x10^3---------10---------------30x10^3-----------73.30
_________W(J)___________Q(J)___________deltaU(J)
A->B_____-8,000________110,000_________102,000
B->C______0__________-90,000___________-90,000
C->A_____8,000_________20,000__________-12,000

Wouldn't the net energy transferred to the system by heat be the sum of the Q values? I get 40,000J for this, but it seems to be wrong. Suggestions would be greatly appreciated.thanks
 
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I know its a bit tedious, but any suggestions?
 

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