Recent content by SUSY
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Graduate Approximate diagonalisation of (3,3) hermitian matrix
Yes, you should be able to diagonalize both simultaneously. In all cases I can think of, $K_0$ will already be a diagonal matrix and $K_{\epsilon}$ is a correction ($K_{\epsilon}$ can in principle be an arbitrary hermitian matrix).- SUSY
- Post #3
- Forum: Linear and Abstract Algebra
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Graduate Approximate diagonalisation of (3,3) hermitian matrix
Hi, I have a 3 by 3 hermitian matrix K that I need to diagonalise. More accurately, I am searching for a unitary matrix S such that S^{\dagger} K S is diagonal. The problem is that K is very complicated and the expression for S in mathematica takes up quiiiiiet a lot of space. Is it...- SUSY
- Thread
- Approximate Hermitian Matrix
- Replies: 2
- Forum: Linear and Abstract Algebra
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Graduate Invariants under group actions
Hey, thanks a lot for that answer! I'll try to read that review by Slansky :) Just one short question concerning this part: Does that mean that \epsilon_{XYZWK} transforms as \epsilon_{XYZWK}\rightarrow \epsilon_{ABCDE} (U^{\dagger})^A_X (U^{\dagger})^B_Y (U^{\dagger})^C_Z...- SUSY
- Post #3
- Forum: Beyond the Standard Models
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Graduate Invariants under group actions
Hi, I am looking to find the invariants of products of fields under SU(5) and other possible gauge groups (but let's take SU(5) as an example). Take, for example, two matter fields in the 5* and 10 and two Higgses in 5 and 5* (called H_{5} and \bar{H}_{5*}). Then the term 5* 10...- SUSY
- Thread
- Group
- Replies: 3
- Forum: Beyond the Standard Models
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Graduate Supergravity = local SUSY or gravity mediation?
Hi, in some texts, the term supergravity refers to locallized supersymmetry but most of the times, I have the impression that it refers to gravity mediated supersymmetry breaking (i.e. higher dimensional terms in the kahler- and superpotential that are suppressed by powers of the Planck...- SUSY
- Thread
- Gravity Local Supergravity Susy
- Replies: 1
- Forum: Beyond the Standard Models
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Graduate Kahler potental terms linear in visible sector fields
Hello, I have a question regarding the expansion of the Kahler potential in visible sector fields C^{\alpha} : It is usually said that the Kahler potential can be expanded as follows: K = K_{hid}(\phi,\phi^*) + K_{\bar{\alpha} \beta}(\phi,\phi^*) C^{*\bar{\alpha}} C^{\beta} + \frac{1}{2}...- SUSY
- Thread
- Fields Linear Terms
- Replies: 1
- Forum: Beyond the Standard Models