Recent content by SweatingBear
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MHB Optimization on non-compact (multivariable)
Been a while since I stopped by here... There's one thing about optimization on non-compact sets that's been bugging me for quite a while and I'd love to hear how you perceive things. Say we are optimizing a partially differentiable (and thus continuous) function $f:\mathbb{R^2} \to...- SweatingBear
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- Multivariable Optimization
- Replies: 1
- Forum: Calculus
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MHB When does the floor function inequality hold?
Let [x] be the floor function i.e. it produces the integral part of x. So for example if x = 1.5 then [x] = 1. I recently saw the claim $$[x] \geq x - 1$$ The strict part of the inequality makes perfect sense, but when does equality occur? Does it even occur at all? I have not been able to...- SweatingBear
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- Function Inequality
- Replies: 1
- Forum: Calculus
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MHB Inequality Proof: Fun Problem | z,w <1 | Forum
The given statement can be written $ |z-w| < |1 - \overline{z}w| $, which equivalently is $ |z-w|^2 < |1 - \overline{z}w|^2 $. Let $ z = a +bi $ and $ w = c + di $. Thus $a^2 + b^2 + c^2 + d^2 < (a^2+b^2)(c^2 + d^2) + 1$, or equivalently, $|z|^2 + |w|^2 < 1 + |z|^2 |w|^2 $. That statement is...- SweatingBear
- Post #7
- Forum: Topology and Analysis
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MHB Inequality Proof: Fun Problem | z,w <1 | Forum
Would you look at that, it was already treated unbeknownst to me (which just nullifies this thread, I'll have it depreciated). Thanks!- SweatingBear
- Post #3
- Forum: Topology and Analysis
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MHB Inequality Proof: Fun Problem | z,w <1 | Forum
Here's a fun problem proof I came across. Show that $$\left| \frac { z- w }{1 - \overline{z}w} \right| < 1$$ given $$|z|<1$$, $$|w|<1$$. I attempted writing z and w in rectangular coordinates (a+bi) but to no avail. Any suggestions, forum?- SweatingBear
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- Inequality Proof
- Replies: 6
- Forum: Topology and Analysis
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MHB Can we prove $3^n > n^3$ for all $n \geqslant 4$ using induction?
I was actually a bit uncertain about that. How else would one go about?- SweatingBear
- Post #3
- Forum: Set Theory, Logic, Probability, Statistics
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MHB Can we prove $3^n > n^3$ for all $n \geqslant 4$ using induction?
We wish to show that $3^n > n^3 \, , \ \forall n \geqslant 4 $. Base case $n = 4$ yields $3^4 = 81 > 4^3 = 64 $ Assume the inequality holds for $n = p $ i.e. $3^p > p^3$ for $p \geqslant 4$. Then $3^{p+1} > 3p^3$ $p \geqslant 4$ implies $3p^3 \geq 192$, as well as $(p+1)^3 \geqslant 125$...- SweatingBear
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- Induction Proof
- Replies: 6
- Forum: Set Theory, Logic, Probability, Statistics
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MHB Why Does Vector Norm Use "Double" Absolute Value?
Fair enough, thanks!- SweatingBear
- Post #4
- Forum: Linear and Abstract Algebra
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MHB Why Does Vector Norm Use "Double" Absolute Value?
Why is it that the norm of a vector is written as a "double" absolute value sign instead of a single one? I.e. why is the norm written as $ || \vec{v} || $ and not $ | \vec{v} | $? I think $ | \vec{v} | $ is appropriate enough, why such emphasis on $ || \vec{v} || $? I think it's rather natural...- SweatingBear
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- Norm Notation Vector
- Replies: 3
- Forum: Linear and Abstract Algebra
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MHB Derivative with respect to which variable?
Yes that's great but I am afraid it does not answer the main question: In the case where we have several variables, how can one tell which variable one should optimize with respect to?- SweatingBear
- Post #3
- Forum: Calculus
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MHB Derivative with respect to which variable?
We have the following trapezoid: The question is to find the length of the fourth side when the area of trapezoid is maximized. I realize we will not be able to find a numerical value for the fourth side due to the given information (rather, lack thereof). So we are essentially going have...- SweatingBear
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- Derivative Variable
- Replies: 5
- Forum: Calculus
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MHB How many real and non-real roots?
Much appreciated you could share your thoughts, Ackbach.- SweatingBear
- Post #7
- Forum: Topology and Analysis
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MHB How many real and non-real roots?
Oh right of course, the trigonometric identities! But here is a follow-up question: How would the issue be resolve if it was the case that we could not take advantage of a trigonometric identity?- SweatingBear
- Post #6
- Forum: Topology and Analysis
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MHB How many real and non-real roots?
How did you end up with $9v = n \cdot 2 \pi$? $9v$ must equal the argument of the number in the right-hand side i.e. $\pi + n \cdot 2\pi$, I see no other way. Excellent! Thanks for that perspective, however I will not rest until I have figured out the nitty and gritty details of my approach...- SweatingBear
- Post #4
- Forum: Topology and Analysis