Recent content by swpz

  1. swpz

    Object drawn across two support points

    Alright. You've been a great help, thank you.
  2. swpz

    Object drawn across two support points

    Ah alright, I see what's going on. So when I used the equations for torque in the OP, I was calculating B, and as such point cg would have been negative, but as we are now calculating point A, cg becomes positive, so in effect it is FB - cg and not + cg. This changes the distance to 0.8776m...
  3. swpz

    Object drawn across two support points

    Suppose we should also define an x/y axis then, dM would become negative if it is stated that B is the initial point on the x-axis with positive right and negative left. As such, the point cg is located -3 units to the left from the initial point of B and would thus become negative. This make...
  4. swpz

    Object drawn across two support points

    Well as my original equation had stated the conditions for CCW motion was to be negative, under the same conditions -- = + At least that is the idea, but I tend to mess up on my sign conventions a lot, could you explain what the issue is here? Thanks
  5. swpz

    Object drawn across two support points

    As follows: Now that we have a figure for FB, we simply plug that into solve for dP I had opted to convert the 600N to g instead of convert everything to N to reduce number of conversions required.
  6. swpz

    Object drawn across two support points

    Hmm okay, so suppose it could mean either 1.9m from initial position or 2.9m from B then. The wording is somewhat ambiguous and open to interpretation as to whether "moved across" means from B or from the initial value.
  7. swpz

    Object drawn across two support points

    ... Oh, well that's... a rather silly oversight on our part. Think got so fixated on the "procedure of B then A that every example just kept using" that lost track of something as basic as this. Afterwards just kept going round and round in circles. Thanks for the reminder. So having done the...
  8. swpz

    Object drawn across two support points

    You mean FA = 600 right? Thought about that, but it doesn't make much sense to me since the sum of Fy doesn't involve distances, the distance part is calculated when FB is calculated. edit: Wait... you're saying do equations in reverse order?
  9. swpz

    Object drawn across two support points

    Homework Statement A 60kg object placed 1m from B is drawn across a beam laid down across two support points. Support point A can only withstand 600N of force before giving way. Support point B is assumed to be capable of withstanding any amount of force. The beam is 6m in length and weighs...
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