Recent content by tacopwn

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    Finding the Path of a Particle in a Temperature Gradient

    (x,y)=(10,10) + t(2,1)
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    Finding the Path of a Particle in a Temperature Gradient

    Oh okay, so once you obtain dy/dx which is 2x/y, how do you make sure it starts at (10,10)?
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    Finding the Path of a Particle in a Temperature Gradient

    The gradient vector at (10,10): dF(x,y)=(-4x,-2x) = (-40, -20)
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    Finding the Path of a Particle in a Temperature Gradient

    The gradient plane at (10,10) is -40x-20y+700=z
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    Finding the Path of a Particle in a Temperature Gradient

    Homework Statement Find an equation for the path of a particle that starts at P(10,10) and always moves in the direction of maximum temperature increase if the temperature in the plane is T(x,y) = 400-2x^2 -y^2 Homework Equations T(x,y) = 400-2x^2 -y^2 dT/dx = -4x dT/dy = -2y...