Recent content by Tautomer22

  1. T

    P = VI = (281V)(3.75A) = 1054 W

    So you're saying I need to focus on the turns ratio of the transformer rather than the resistance in ohms? I understand what you're saying, but I suppose I attacked this problem under the assumtpion that I would solve it by 1) Finding the power at the power plant 2) Finding the power...
  2. T

    P = VI = (281V)(3.75A) = 1054 W

    I understand your logic, but it's the numbers I don't understand... With an resistance of 75 ohms and a current of 3.75, the voltage I calculate is = 281 V (which is very far off from the expected 240,000 V). Also, if I simply use a power equation, such as I2R then I get a power equal to 1054 W...
  3. T

    P = VI = (281V)(3.75A) = 1054 W

    Homework Statement A small power plant produces a voltage of 6.0 kV and 150 A. The voltage is stepped up to 240 kV by the transformer before it is transmitted to a substation. The resistance of the transmission line between the power plants and the substation is 75 Ohms. What percentage...
  4. T

    Electic Flux through a cube Why am I getting a value?

    I was unclear on this point, thank you so much gneil! That solves the whole issue for me. I knew I was missing a basic idea here, and I wasn't deducing it from solutions to similar problems (alas).
  5. T

    Electic Flux through a cube Why am I getting a value?

    Homework Statement A cubical Gaussian surface is placed in a uniform electric field as shown in the figure to the right. The length of each edge of the cube is 1.0 m. The uniform electric field has a magnitude of 5.0 * 10^8 N/C and passes through the left and right sides of the cube...