Recent content by terff

oops I realize another mistake I did in that equation $$\Delta y = v_0\sin\theta\left(\frac{\Delta x}{v_0\cos\theta}\right) + \frac{1}{2}a\left( \frac{\Delta x}{v_0\cos\theta} \right)^2$$ is correct, the squared is in the wrong place in my fraction. -0.268 = v(0.866)(\frac{3.78}{v(0.5)}) +...

Ahh my apologies, ∆y = v(sinθ)(\frac{∆x}{v0(cosθ)}) + \frac {1}{2}(a)(\frac{∆x}{v0(cosθ)^2}) is the equation, and yes that is what I wrote. In my final equation \sqrt{\frac{2a∆x}{2∆y(cosθ)^2 - (cosθ)(sinθ)(∆x)}} = v substituted the following variables θ angle= 60º ∆x= 3.78 m ∆y= -.268 m ay=...

Homework Statement So I have a group lab for physics, but I need some alg/trig help isolating v for a derived equation. I've tried many times to to get v0 by itself but when I check the equation with the values that I have for each variable I always get the wrong answer. ∆y =...