Recent content by tgould43

My mind keeps thinking that there is some relationship between the displacement of the 2.5 m/s velocity of the first block after it left the spring. Is this something that is valid?

would the equation change by the new equation of 3.0kg x 9.8 ms / .06 = 490 N/m

If a spring is originally compressed by 6cm, what is the force of the spring constant? A block of inertia m=0.2kg is launched from a spring onto frictionless surface. The velocity is 2.5m/s upon leaving the spring. I used Hooke's law and got k=mg/x 0.2kg x 9.8m/s / 0.06m = 32.7 N/m The next...