Recent content by thatnewkid

Does anyone know a good websites to help with circuit problems and stuff? i have a final tomorrow that has a majority or problems on this and it was last semester and i don't remember much :P

ok so m=hi/ho is equal to -9.4 now what?

wow ok thankyou haha could you help me with the height and magnification? hold on ill show you what i got so far...

so that is 9.4 would it be right at 2f with the object?

so... 875(346.54-27/346.54 + 0)= 806.826Hz?

ok i just got so confused, help me out with what your trying to get at? (sorry i may seem dumb but i haven't done this in a long time and I am trying to learn it again to prepare for my final)

V of sound = 331 + .6(temp)=331 + .6(25.9)=346.54m/s f = actual f (v - v of observer/ v+ v of source) f= 875(346.54/346.54 +27) f= 811.75Hz

no nm i think i got it is it 811.75Hz?

alright so i have f1= 875(v-27/v+vs) how do i find the speed of the source with the temperature? v=speed of wave vo=speed of observer vs=speed of source f=frequency at source f'=frequency observed by observer.

2/1 then? I am sorry I am just so confused on this subject! :/

is it 0.36518857142857? i understand what the source velocity is and the initial wavelength frequency is but i think i may have messed up where temperature plays a role

ok ok hold up I am trying it

i haven't herd of that but I am guessing that's possible...how does that work?

So a factory whistle emits a sound at 875Hz. The temperature of the air is 25.9oC. What frequency will be heard by an observer in a car traveling at 27m/s away from the source i know this is a two step problem but i have no idea where to start! anyone lead me in the right direction?

1/f=1/di+1/do 1/4.7=1/di+1/9.4 so di equals .106383? for distance?