Recent content by ThatOneGuy

Homework Statement Evaluate the Improper integral [4,13] 1/(x-5)1/3 Homework Equations N/A The Attempt at a Solution In step 1, I split the integral into two separate integrals because at x=5, it would be undefined. I made the first limit approach 5 from the left and the second limit...

Thank you so much! I should have noticed the reducing. Finishing the problem: sec-1(2) - sec-1(21/2) sec-1(2) - sec-1(√(2)) This equals: arccos(1/2) - arccos(1/√(2)) arccos(1/2) - arccos(√(2)/2) pi/3 - pi/4 = pi/12

Homework Statement [23/4, 2] 4/(x√(x4-4)) Homework Equations ∫ du/(u√(u2 - a2)) = 1/a(sec-1(u/a) + c The Attempt at a Solution I first multiplied the whole thing by x/x. This made the problem: 4x/(x2√(x4 - 4)) Then I did a u substitution making u = x2. Therefore, du = 2xdx. I multiplied by...