1. The problem statement, all variables and given/known data [23/4, 2] 4/(x√(x4-4)) 2. Relevant equations ∫ du/(u√(u2 - a2)) = 1/a(sec-1(u/a) + c 3. The attempt at a solution I first multiplied the whole thing by x/x. This made the problem: 4x/(x2√(x4 - 4)) Then I did a u substitution making u = x2. Therefore, du = 2xdx. I multiplied by 2 to get 2du = 4xdx The problem then becomes 2∫du/(u√(u2 - 4)) Solving the integral I got 2[(1/2)sec-1(x2/2)] from [23/4, 2] I plug in the bounds and get 2[(1/2)sec-1(2) - (1/2)sec-1(26/4/2) This is where I'm lost. The second sec does not seem like a nice number and I'm assuming my professor would make the problem come out nicely as he always has. I'm pretty sure I made a mistake somewhere because of this but I don't know where.