# Evaluate the Improper integral [4,13] 1/(x-5)^(1/3)

1. Apr 12, 2015

### ThatOneGuy

1. The problem statement, all variables and given/known data

Evaluate the Improper integral [4,13] 1/(x-5)1/3

2. Relevant equations

N/A

3. The attempt at a solution

In step 1, I split the integral into two separate integrals because at x=5, it would be undefined. I made the first limit approach 5 from the left and the second limit approach five from the right.

For step 2, I did u substitution to prepare to integrate. Since I did the substitution, I plugged the old intervals into u = x - 5 to get the new ones.

For step 3, I rewrote both integrals in terms of u du and brought the u^(1/3) from the denominator to the numerator for easier integration. I also added the new intervals in.

In step 4, I integrated both integrals.

Step 5 is where I'm not sure what to do. I plugged in the values and that is what I ended up with but in the first parentheses, the second value has a (-1)2/3 which is undefined. The (R-5)'s will equal 0 and cancel those fractions out but I don't know how to handle the (-1)2/3.

2. Apr 12, 2015

### Staff: Mentor

$(-1)^{2/3}$ is defined -- its value is 1.

You can work with it either as $[(-1)^2]^{1/3} = 1^{1/3} = 1$ or as $[(-1)^{1/3}]^2 = (-1)^2 = 1$.