Recent content by The CdePster

Ha thriller i remember these questions man, I'm like oh no how on Earth can i do this when i don't know the mass?! But setting E=05mv^2 and E=mgh equal to each other sound like a grand plan if you want to get rid of those cheeky masses! Cuz don't forget they should equal each other at the bottom...

It gives you the amplitude in the question lol! :) It say the maximum displacement(aka the amplitude) at time t=0 is 2cm. Hence the amplitude 2 wavelengths down is the same. The wavelength is the distance from peak to peak or from one point in the same place to another on the wave. do you get...

Hmm i don't understand your method at all ha! There should be no eV/s it should be in J/s. OK here goes ill try and explain it, try and do it my way because i think its more intuitive :). Watts = the amount of joules evolved per second. First part to realize which you got. Secondly 1eV=1.6E-19...

Nope, i believe that the equation for the displacement is x=x0 cos(omega*t) where omega(the greek symbol that looks like a pair of melons ;)) is the angular frequency and the angular frequency can be found by doing this omega= 2pi*f. And x0 is the amplitude, not the wavelength. Draw a cosine...

Heya m8! Firstly in the equation you are using I assume by frequency you mean angular frequency?? It is the right equation though. Also I believe that if you use v=f*wavelength and rearrange to get the wavelength you get a stunning answer which is a 'bizarrely' a multiple of the distance that...

Hiya! You're almost there m8 but one thing you got to remeber is that 1eV is equal to 1.6E-19 joules. so 2.5eV is what?? And then youre virtually there, because your right and watts are J/s and that thing is emitting 0.5 J/s. Ha and just realized because i didnt check your first method is...

Just in addition, I think you can also use the equation a=-ang freq^2 * max displacement. Its much faster, however you get an answer of 70s^-1 for the angular frequency. Which is more accurate i do not know. Somebody'll probably tell me I am wrong now. :)

thanks for the reply, i used the amplitude of oscillation 5.5E-10 for 'x' or rather 'x0' As it would be in this case. Because x0 is the same as amplitude yes? Even if I had used the wrong value for x which i don't think I have surely I can't be one billion out as the answer would suggest...

Homework Statement In a simple atomic model of a solid, the atoms vibrate with a frequency of 2E-11 Hz. The amplitude of the vibration of the atoms is 5.5E-10 m and the mass of each atom is 4.8E-26. Calculate the total energy of the oscillations of an atom. Homework Equations total...