Recent content by TheNarrator

Thanks for your response. So that means the handle assembly is fastened to the exterior stationary pole in some way correct? I need to make a system like this where the threaded rods extends but want it to rotate through 360deg (preferably only once) as it extends. is there a way to achieve...

Firstly, am struggling to wrap my head around exactly how the mechanism for a traditional 'hills hoist' (as seen below) clothesline functions. The handle can be turned in order to raise the clotheslines but from my googling, the mechanism is different to what I was expecting. Would be...

Okay so now I have (-Va/8)-(Va/6)-(Va/4)=(-4/6)-(12/4) Which gives Va as 6.77V and a corresponding i of -1.31A The negative current means i is flowing the opposite way to what I have marked (towards top of diagram)

Oh of course! brain fade.. I calculated Va as 12.57V so therefore i has a value of (12.57-12)/4 = .143A Thanks for your help! I will attempt to solve the thevenins problem by myself but will post later if I can't get there

Okay cool, so if i1+i2+i=0 Then (-Va/8)+((Va-4)/6)+((Va-12)/4)=0 But I can't work out how to solve for Va from here, is there another equation I am meant to be using to solve with substitution?

This shows what I have attempted, I think where I am going wrong is the way I am doing the voltage differences but I am really struggling to understand specifically where I am going wrong

Thanks for your replies everyone, just at work atm but will mark up the diagram and post my current calculations tonight

I understand that part, however I thought that the equations I had put in my attempted solution were in terms of voltage differences and the three voltages? I thought that the way the circuit was laid out, all three voltage differences would be dependent on Va?

Homework Statement Am having trouble solving the initial part of this problem, I think I am being confused by the dual voltage sources. 2. Homework Equations I=V/R ΣI at a node =0 The Attempt at a Solution V3/R3 - (V1/R1+V2/R2) = 0 V3=12-VA V1=4-VA V2=VA-4 However this must be incorrect...