Recent content by ThePiGeek314

No, because the only weight on the rope would be Superhero's weight of 882 N. Using Newton's Third Law, the tension in the rope above Superhero would also be 882 N, right? Using common sense, the tension in the rope below where Superhero is hanging on should be 0...but isn't tension supposed...

Thanks! I did wonder about the small difference in the orbit radii, but wasn't sure if I was missing something.

I'm pretty confident with drawing free-body diagrams. I just posted one from the Internet because it would have been more hassle to draw my own, take a picture, upload it, and post it.

Homework Statement A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.70 × 104 m/s, and the radius of the orbit is 5.25 × 106 m. A second satellite also has a circular orbit around this same planet. The orbit of this second satellite has a radius of...

Is this why each of the ropes in a single pulley only has tension equal to HALF the weight in the entire pulley system?

Homework Statement Two similar questions here. I have the same question regarding solutions to both. Calculate the tension in a horizontal strand of spider web if a spider of mass 8.00 × 10−5 kg sits motionless in the middle of it. The strand sags at an angle of 12° below the horizontal. A...

Homework Statement [/B] Superhero and Trusty Sidekick hang motionless from a rope. Superhero’s mass is 90.0 kg, while Trusty Sidekick’s is 55.0 kg, and the mass of the rope is negligible. (a) Draw a free-body diagram of the situation. (b) Find the tension in the rope above Superhero. (c)...

Got it - because the 0.854 N was calculated as a function of the force of gravity - 9.8 sin Θ, so it's the gravitational force pulling the skier down the hill. Thank you!

Homework Statement Calculate the deceleration of a snowboarder going up a 5.0° slope, assuming the coefficient of friction for waxed wood on wet snow ( = 0.1). Homework Equations F = ma W = mg Fs = (Fn) Fk = k (Fn) The Attempt at a Solution Answer key says it's 1.83 m/s2. I fiddled...