Recent content by ThrawnGaming

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    Gauss's Law for a sphere with a cavity, solving for E(r)

    Thank you soooo much! I think I understand now. I have ##\rho(4/3 \pi r^3 - 4/3 \pi R_1^3)##
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    Gauss's Law for a sphere with a cavity, solving for E(r)

    Is this correct?
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    Gauss's Law for a sphere with a cavity, solving for E(r)

    I want to find E as a function of r, and I think I have to integrate to do that.
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    Gauss's Law for a sphere with a cavity, solving for E(r)

    This is AP Physics C, and I am currently taking AP Calculus AB
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    Gauss's Law for a sphere with a cavity, solving for E(r)

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    Gauss's Law for a sphere with a cavity, solving for E(r)

    I tried integrating for 4/3 pi r^3 with r= 0.04 to r=0.12, and I found that the charge decayed exponentially from r=0.04 (1/r^2), but I know that is incorrect, because for volume charge densities, it should increase from r=0.04...
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    Gauss's Law for a sphere with a cavity, solving for E(r)

    I am not sure how to solve for E(r) for R1<r<R2.