Recent content by tiger1

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    Electrical field of an equialateral triangle

    Thanks.. Figured it out. Also figured out I was calculating the triangle height wrong.
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    Therefore, the focal length of the mirror is -1m.

    Solved: m=-s'/s=1/2 -s'=s/2 |s'|=s/2 |s|+|s'|=1.5 |s|+|s/2|=1.5 3/2s=1.5 s=1 |s|+|s'|=1.5 |s'|=1.5-|s| s'=1.5-1 s'=.5 but since s' is negative for virtual, upright images s'=-.5 1/f=(1/1)+(1/-.5)=-1 f=-1m
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    Therefore, the focal length of the mirror is -1m.

    -.5=-s'/s s=-s'/-.5 s+s'=1.5 -s'/-.5 + s' = 1.5 (1/2)s' + s' = 1.5 (3/2)s'=1.5 s'=1 s+s'=1.5 s=1.5-s' s=.5 1/f=(1/.5)+(1/1)=3 f=1/3=.33m Which is still wrong.
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    Therefore, the focal length of the mirror is -1m.

    Setting m negative gave me the same answer -.5=s'/s s=s'/-.5 s+s'=1.5 s'/.5+s'=1.5 -(1/2)s'+s'=1.5 s'/2=1.5 s'=3 According to my book, s' should be negative, though, because we have a virtual image on the opposite side of the object. Continuing anyways... s=1.5-s' =-1.5...
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    Therefore, the focal length of the mirror is -1m.

    [SOLVED] Focal length of a mirror Homework Statement A 2.0-cm-tall object is placed in front of a mirror. A 1.0-cm-tall upright image is formed behind the mirror, 150 cm from the object. What is the focal length of the mirror? Homework Equations 1/f=1/s+1/s' m=h'/h m=-s'/s...
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    Index of refraction in an air bubble

    [SOLVED] Index of refraction Homework Statement An air bubble inside an 9.00 cm-diameter plastic ball is 2.90 cm from the surface. As you look at the ball with the bubble turned toward you, how far beneath the surface does the bubble appear to be? Homework Equations n_1/s + n_2/s' =...
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    Goldfish bowl index of refraction

    Homework Statement To a fish in an aquarium, the 4.30 mm-thick walls appear to be only 3.10 mm thick. What is the index of refraction of the walls? Homework Equations m=-s'/s n_1/s + n_2 / s' = (n_2-n_1)/R m: magnification s: object distance s': image distance The Attempt at a...
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    How Do You Convert dB to W/m^2 for a Test?

    Homework Statement I have a test coming up and I need to be able to convert dB to W/m^2 and vise versa. Could someone please explain to me how to do this? Homework Equations B=(10dB) log_10(I/I_0) I_0 = 1.0*10^-12W/m^2 The Attempt at a Solution Google, came up with nothing
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    Two in-phase loudspeakers on a coordinate plane

    Figured it out using A=|2a cos[1/2(change in phi)]|
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    Two in-phase loudspeakers on a coordinate plane

    Homework Statement Two in-phase loudspeakers are located at (x, y) coordinates (-3.0, +2.0) and (-3.0, -2.0) . They emit identical sound waves with a 2.0 m wavelength and amplitude a. Determine the amplitude of the sound at the five positions on the y-axis (x=0): with y=0.0 with y=0.5 with...
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