Recent content by tigers4
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Solving Ideal Gas Problems: ΔE, ΔS, W & P0V0
a.) ok, W=nRTln(Vf/Vi) p0v0=nRT (nRTln(Vf/Vi))/nRT=ln(Vf/Vi) b.) deltaEint=nCv(deltaT) c.)0 d.)? e.)0- tigers4
- Post #3
- Forum: Introductory Physics Homework Help
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Solving Ideal Gas Problems: ΔE, ΔS, W & P0V0
Homework Statement 1.0 mol of a monatomic ideal gas is taken through the cycle in the figure below. http://s1142.photobucket.com/albums/n603/bdoneski/?action=view¤t=20-26.gif" a) What is the following as the gas goes from state a to state c along path abc? W0/P0V0 (b) What...- tigers4
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- Gas Ideal gas
- Replies: 3
- Forum: Introductory Physics Homework Help
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How Does Entropy Change and Work Done Relate in a Reversible Ideal Gas Cycle?
nevermind i solved it- tigers4
- Post #2
- Forum: Introductory Physics Homework Help
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How Does Entropy Change and Work Done Relate in a Reversible Ideal Gas Cycle?
Figure 20-29 shows a reversible cycle through which 1.00 mol of a monatomic ideal gas is taken. Assume that p = 2p0, V = 2V0, p0 = 1.13*10^5 Pa, and V0 = 0.0235 m^3. Fig. 20-29 http://s1142.photobucket.com/albums/n603/bdoneski/?action=view¤t=hrw7_20-29.gif" (a) Calculate the work done...- tigers4
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- Change Entropy Work Work done
- Replies: 1
- Forum: Introductory Physics Homework Help
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Isobaric Process: Finding Work Done by Ideal Gas
change in internal energy U=Q-W change in internal energy=heat added-work done by system- tigers4
- Post #5
- Forum: Introductory Physics Homework Help
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Isobaric Process: Finding Work Done by Ideal Gas
constant pressure- tigers4
- Post #3
- Forum: Introductory Physics Homework Help
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Isobaric Process: Finding Work Done by Ideal Gas
Homework Statement When 23.3 J was added as heat to a particular ideal gas, the volume of the gas changed from 54.7 cm3 to 100 cm3 while the pressure remained at 1.00 atm. (a) By how much did the internal energy of the gas increase? J (b) If the quantity of gas present was 2.00 10-3...- tigers4
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- Gas Ideal gas
- Replies: 5
- Forum: Introductory Physics Homework Help
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How Do You Solve an Oscillating Rope Problem?
the second harmonic has three nodes- tigers4
- Post #3
- Forum: Introductory Physics Homework Help
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How Do You Solve an Oscillating Rope Problem?
Homework Statement A rope, under tension of 120 N and fixed at both ends, oscillates in a second-harmonic standing wave pattern. The displacement of the rope is given by y = (1.18 m)sin ( x / 2) sin (10 t), where x = 0 at one end of the rope, x is in meters, and t is in seconds. (a)...- tigers4
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- Oscillating Rope
- Replies: 3
- Forum: Introductory Physics Homework Help
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When do two pulses begin to meet?
Homework Statement A 140 g wire is held under a tension of 200 N with one end at x = 0 and the other at x = 7.0 m. At time t = 0, pulse 1 is sent along the wire from the end at x = 7.0 m. At time t = 30.0 ms, pulse 2 is sent along the wire from the end at x = 0. At what position x do the...- tigers4
- Thread
- Replies: 2
- Forum: Introductory Physics Homework Help
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Hollow iron spherical shell submerged in water, find the inner diameter
yes everything looks good, the diameter is 63.1 cm- tigers4
- Post #10
- Forum: Introductory Physics Homework Help
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Calculating Rise of Mercury in U-tube with Water
Homework Statement A simple open U-tube contains mercury. When 12.3 cm of water is poured into the right arm of the tube, how high above its initial level does the mercury rise in the left arm? Homework Equations density of water=1000kg/m^3 density of mercury=13534 kg/m^3 The...- tigers4
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- Mercury Rise U-tube Water
- Replies: 1
- Forum: Introductory Physics Homework Help
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Hollow iron spherical shell submerged in water, find the inner diameter
it says that my answer is incorrect, I multiplied 32.998 by 2 and got 65.996, but its not correct- tigers4
- Post #8
- Forum: Introductory Physics Homework Help
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Hollow iron spherical shell submerged in water, find the inner diameter
wow lol, thank you for all the help you are a life saver.- tigers4
- Post #7
- Forum: Introductory Physics Homework Help
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Hollow iron spherical shell submerged in water, find the inner diameter
Fb=1475.2136N/9.8=actual mass of sphere mass of sphere=150.532 mass whole iron sphere-mass of actual sphere=mass of inner sphere=1184540.665 7.87=1184540.665/V rinner=32.998 cm but that's incorrect, where is my error?- tigers4
- Post #5
- Forum: Introductory Physics Homework Help