And that's calculated by using the {I}_{n+1} formula with to obtain that result?
and then the results for S and I are inputted to each of the formulas sequentially? And then the same for the R formula?
Thanks..
So to graph that function, you would then input the {S}_{1} result back into the formula. How do we produce the result when the formula requires the subsequent I value? Or does n value for I remain at a constant?
Thanks
Hi,
thanks for the info.
To input values to the formulas.. with the example of S..
S(0)= {S}_{0} = 3
I(0) = I{S}_{0}= 5
h= 0.5
\beta=1
\gamma=2
Sn+1 = Sn +(h.-\betaSnIn)
Sn+1 = 3 +(0.5.-1.3.5)
Sn+1 = -4.5
Is that right? Thanks
Question on SIR Model and using Eulers method for approximating a solution.
Given the 3 ODEs of the SIR model
dS/dt = -\betaSI
dI/dt= -\betaSI - \gammaI
dR/dt = \gammaI
Ive been asked to produce in excel Eulers method for axproximate solutions. Given some initial values for S(0) and I(0) as...
Hi,
got a question I'm stuck on..
Write down a matrix P which will diagonalise A and write down the corresponding
diagonal matrix D, where D = P^-1AP. You do not have to calculate P^-1
Ive got all the eigenvalues and eigenvectors for A, and thus have the Matrix P, which has a determinant of...
Hi,
yeah really struggling with this one.
So as its listed as a differential application, I've assumed there would be a First or Second Order differential to apply.
if a(t) = t just doesn't seem to be a lot to go on.
I can only think of integrating a(t) and then solving for t with the second...
so do we need to bring the Volume formula back into represent V and R
if V =4/3pi.r^3
then r = (3V/4pi)^1/3r0=-kt +c
(3V/4Pi)^1/3 =-kt+c
is that the right path?
Thanks
hi,
anti derivative of a(t) = 1/2at^2
anti-derivative of 1/2at^2 = 1/6at^3
which doesn't look like any of the kinematic equations.
Still puzzled by this one as S= S(i) + V(i)+ 1/2at^2 which the derivative will give you a(t). Then solve with S = 100m
Any advice appreciated
Thanks
So,
dr/dt = -k
dr = -k.dt
intergral dr = integral -k.dt
r = -kt + c
0 = -kt +c
Still not sure that's it, or should it be that the integral of -k.dt is -1/2k^2t
Thanks
Hi,
another question I am having trouble with
so my thought at the moment is to integrate a(t), which results in 1/2at^2 which is the kinematic equation for distance and then solve for the equation to equal 100.
Just doesn't seem right to me and possibly too easy a solution.. think I am...
Hi,
need some help on the following question.
Just want to check on part a on the followingv=4/3\pi.r^3
dv = 4\pi.r^2 dr
dv/dt = 4\pi.r^2 dr/dt
dr/dt = (dv/dt)/ 4\pi.r^2
dr/dt = (-KA)/4\pi.r^2
dr/dt= -K
part B need some help
Thanks
Tom
Hi, Also need some help on a following question to this same problem.
need work on optimisation for the values of A+B
I tried optimising by implicit differentiation of a right and angled triangle, however the values I get are out side of the given range
12. we change the values of a and c...
Hi Thanks for the help, glad to see I wasn't too far off.
One thing for the formula for B, i reached the formula by creating 'h' to represent the height of the joint of A+C, and then split B in B1 and B2 at h to create to right angle triangles.
B=B1 + B2
B1 = Acos\theta
B2 = \sqrt{C^2 -h^2}
h...
Hi,
Looking for some help on a crank/piston motion equation..
If a crank rotates counter clockwise measured in Radians/sec -as d\theta/dt = K T = time in secs
The arms of the crank A and B are fixed and B is the stroke length with \theta as the angle between A and B
So far I've got that B =...