Recent content by topu87
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Undergrad What is the error in this proof?
sorry look at this form. This is more understandable than the previous one 1= \sqrt{1} = \sqrt{(-1) (-1)}= \sqrt{-1}\sqrt{-1} = [FONT="Times New Roman"]i [FONT="Times New Roman"]i = [FONT="Times New Roman"]i^{2} = -1- topu87
- Post #2
- Forum: General Math
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Undergrad What is the error in this proof?
please tell me where is the error here- 1 = \sqrt{}1 = \sqrt{}(-1) (-1) =\sqrt{}-1 \sqrt{}-1 = i^{}2 = -1 so we get 1= -1. what is the error here?- topu87
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- Error
- Replies: 6
- Forum: General Math
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Charging a capacitor with a switch
i think charge can flow upto the point where the switch is connected. After that there is no conducting path for flowing of the charge. But Imn't sure of it.- topu87
- Post #2
- Forum: Introductory Physics Homework Help
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Friction Mass Loss: Formula to Find Lost Mass
When a solid body is moving on any hard surface due to friction it will lose some very little part of its body; as when we take a broken piece of glass and rub it on the concrete surface, it loses some mass of its initial mass. so, what is the general formula of finding the lost mass due to...- topu87
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- Friction Loss Mass
- Replies: 1
- Forum: Materials and Chemical Engineering