Recent content by Torrie

Sorry but I still have no idea where to go with this. Thanks for your help though.

I can't figure out how to isolate P1 to solve for it. I don't know how to get it out of the log.

So then it is: 1B = log10(P1/130)? And I am looking for P1?

I have tried to look it up online. I see this equation: RatioB = log10(P1 / P0) So I tried log10(1150/15300) = -1.12399 But I don't know what this number is. I am assuming bels. So I would get -11.24 dB, but I don't know how I would turn that into watts. I tried 10^-11.24 = .000000000005754. I...

Well I initially tried: 1150/15300 = 0.075 to get the ratio. And multiplied that by 130. But I know that can't be it because I don't think the relationship is linear like that. I don't know where to start because I don't understand the relationship between dB, Intensity, Watts and R

Homework Statement A stereo amplifier is rated at 130W output at 1150Hz. The power output drops by 10.0dB at 15.3kHz. What is the power output in watts at 15.3kHz? Homework Equations R=I/Io Io = 10^-12 w/m2 bel = log(r) The Attempt at a Solution I have no idea where to start

Thank you so much!

Okay so then I have .001049(285.12^2) = 85.277 So the tension would need to be 85.277N?

Should μ be kg/m? So... 0.00034/.324m = .001049kg/m?

Now I realize that v = 285.12. I forgot to multiple length by 2 to get the wavelength. But I still can't figure out the second equation

Homework Statement The A string on a violin has a fundamental frequency of 440Hz. The length of the vibrating portion is 32.4cm and has a mass of 0.340g. Under what tension must the string be placed? Homework Equations V = Fλ Vs = √t/μ The Attempt at a Solution I plugged in my info to...

Okay that makes sense! 3943.995 x .1 = 394.3995 n/m Thank you so much for all of your help!

Okay why would I square the 2π? Sorry I just want to make sure I am clear. Thank you so much for your help. f = 1/2π x √s/m f^2 = 1/(2π)^2 x s/m 10^2 = 1/39.4384 x s/.01 100 = .025355 x s/.01 100 / .025355 = s/.01 3943.995 x .01 = s 39.43995 = s

Okay, so f= 1/2π x √s/m f^2 = 1/2π x (s/m)^2 10 = 1/2π x s/.1^2 10 = 1.57 x s/.01 10/1.57 = s/.01 6.369 x .01 = s .06369 = s?

Well I tried to isolate s, but I can't figure out how. f = 1.57 x √s/100 10/1.57 = √s/100 6.369 x 100 = √s 636.94267^2 = s 405695.97 but I know this can't be right.