Sound & Music - Tension of a string

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Homework Help Overview

The problem involves determining the tension required for a violin string given its fundamental frequency, length, and mass. The context is within the subject area of wave mechanics and string vibrations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of wave speed and tension using the relationships between frequency, wavelength, and linear mass density. There are attempts to correct initial calculations and clarify unit conversions.

Discussion Status

The discussion has progressed with participants verifying calculations and unit conversions. Some guidance has been provided regarding the correct units for linear mass density, and there is a recognition of the need for significant figures in the final answer. Multiple interpretations of the calculations have been explored.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the extent of guidance provided. There is an ongoing clarification of assumptions regarding units and calculations.

Torrie
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Homework Statement



  1. The A string on a violin has a fundamental frequency of 440Hz. The length of the vibrating portion is 32.4cm and has a mass of 0.340g. Under what tension must the string be placed?

Homework Equations


V = Fλ
Vs = √t/μ

The Attempt at a Solution


I plugged in my info to determine V = 142.604
then I attempted the second equation as:
T = .340(142.604^2)
This gave me the wrong answer
I also tried:
T = 1.049(142.604^2) - (.340g/.324m = 1.049g/m)
This also gave me the wrong answer. I am not sure what to do
 
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Now I realize that v = 285.12. I forgot to multiple length by 2 to get the wavelength.
But I still can't figure out the second equation
 
Torrie said:
Now I realize that v = 285.12. I forgot to multiple length by 2 to get the wavelength.
But I still can't figure out the second equation
Make sure that your units all match (pay attention to your units for μ).
 
Should μ be kg/m?
So... 0.00034/.324m = .001049kg/m?
 
Torrie said:
Should μ be kg/m?
So... 0.00034/.324m = .001049kg/m?
Yes.
 
Okay so then I have

.001049(285.12^2) = 85.277

So the tension would need to be 85.277N?
 
Looks right to me. Be sure to round to the required number of significant figures.
 
Thank you so much!
 

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