Recent content by TRed503
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Tension of 10 m rope hung across 6 m horizontal distance with 50 kg box hanging
I think I figured it out... I was interpreting the problem to mean that the mass is 4 m horizontal distance from point A, but I think that the 4 m was supposed to be the length of T1 or the hypotenuse for my right triangle! If only story problems came with pictures! Thanks for you're reply...- TRed503
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- Forum: Engineering and Comp Sci Homework Help
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Tension of 10 m rope hung across 6 m horizontal distance with 50 kg box hanging
Yes that is correct. Not sure if that was a statement or a question, but I'm past that part, drew my diagram and am stuck trying to suck Newtons out of meters and no angles somehow?- TRed503
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Tension of 10 m rope hung across 6 m horizontal distance with 50 kg box hanging
Homework Statement A rope is 10.0 m long and is attached at points A and B, which are at the same elevation 6.0 m apart. If a 50.0 kg mass is attached to the rope 4.0 m away from point A, what is the tension in the two segments of the rope? Homework Equations W = ma ƩFy = 0 = T1 + T2 - W...- TRed503
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- Box Horizontal Rope Tension
- Replies: 3
- Forum: Engineering and Comp Sci Homework Help