# Tension of 10 m rope hung across 6 m horizontal distance with 50 kg box hanging

## Homework Statement

A rope is 10.0 m long and is attached at points A and B, which are at the same elevation 6.0 m apart. If a 50.0 kg mass is attached to the rope 4.0 m away from point A, what is the tension in the two segments of the rope?

## Homework Equations

W = ma
ƩFy = 0 = T1 + T2 - W
ƩFx = 0 = T1 + T2

## The Attempt at a Solution

W = 50.0 kg * 9.81 m/s^2
I'm stuck after finding the weight of the hanging mass as no other angles or forces are given? I tried using 6.667 m and 3.333 m as the respective lengths for T1 and T2 assuming that the ratio of 2/3 distance of the hanging mass between point A and B would be the same ratio on the rope length. Then tried to use trig to get the vertical hanging distance but came up with 2 different distances so these numbers don't work. I'm lost and stuck as to were to go. Any help is much appreciated as this homework assignment is already late and I've spent about 5 hours reading and looking up stuff online with no success! Feel as though I'm trying to extract blood from a rock!

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