Recent content by trumnation

Ok so I tried that, and I think I have an error somewhere because it doesn't work. Here is what I did: t = 9/(Vsin49) 2.43 = 1.61 + Vcos49t - 0.5*9.8t^2 0.82 = Vcos49 * 9/Vsin49 - 4.9 * (9/Vsin49)^2 V = 7.9 m/s I can't seem to find what I did wrong though..

Ok, how though, do I find the time? Or should I solve for t in the x equation and sub it in?

Homework Statement A regulation volleyball court is L = 18.0 m long and the net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.61 m directly above the back line, and the ball's initial velocity makes an angle θ = 49° with respect to the ground. At what initial speed...