Imagine the following scenario. A pipe is strapped to a larger "host" pipe using a steel strap and a spacer block as shown in the image below. If anyone could have a look at my calculations to confirm they are correct that would be brilliant!
Variables
Assuming the following general values I...
Hi there!
Im trying to do an analysis in Abaqus of a cantilever pipe, with a tip mass at the free end, that is decelerating to a stop at 10 m/s2 from 10m/s, causing it to vibrate. The pipe is vertical, fixed at the top with the mass at the bottom, and it is moving in the x axis. To validate my...
Hi there!
Im trying to do an analysis in Abaqus of a cantilever pipe, with a tip mass at the free end, that is decelerating to a stop at 10 m/s2 from 10m/s, causing it to vibrate. To validate my results I am doing some handcalcs. I have done a static analysis and calculated the maximum...
Hi all
I was just wondering if anyone could help me with estimating error caused by misalignment of an optical arrangement. I am interested in how the focal length of this arrangement will be affected by say a misalignment of just one of the lenses. I'll assume that every component is aligned...
Homework Statement
The translational system in the first attachment represents the rear/front suspension of a car of mass 1262kg. The distance between the axles is 2.41m and the distance between the centre of mass and the front axle is 1.22m.
I am told that:
m2 = 40 kg
c1 = 800 Nm/s
k1...
ahh! I've been using sin instead of cos! i can't believe i did that.
so I've integrated
2/T ∫ f(t)*sin(n*π*t/T) dt between 0.5 and 0
and i get:
(22*cos(pi*n) - 11*n^2 *pi^2 + 22*n*pi*sin(n*pi) -22)/(2*(n^3 * pi^3))
since I've integrated for only half the period and between 0 < t <...
so for 0 < t < 0.5, f(t) = 5.5 - 22*t^2 ?
then do i add the integral of:
f(t)*cos((2*pi*n*t)/T) dt between -0.5 < t < 0
and -f(t)*cos((2*pi*n*t)/T) dt between 0 < t < 0.5
because won't that just equal zero?
well I am not really sure what to use as the bounds for the integral... i got confused when it said the period was 1 but the function is only true between -0.5 < t < 0. i know since its odd its asymettric about the vertical axis and since its periodic it might have something to do with that? i...
Homework Statement
f(t) is an odd, periodic function with period 1 and:
f(t) = -5.5 + 22*t2 for -0.5 ≤ t < 0
i) find the Fourier coefficient bn
ii) find the Fourier coefficient b5
Homework Equations
bn = (2/T) * ∫ f(t) *sin((2*n*∏*t)/T) dt between T/2 and -T/2...
yes it is, i was trying that before but my answers kept coming up different to those given. i must have made some mistake when i rearranged the denominator. thanks for your tips :-)