Recent content by twotoes777

Oh my goodness, yes, you are right. Thanks for the help... I got it now, and that makes sense. I was wondering how it would matter if the piece went forward and not backwards. Thanks again. :)

Clarification.. Thanks for responding! Here we go... m1(v1)+m2(v2)+m3(v3) = m(total)v(total) (4.6*10^5)(2.1*10^6) + (8.3*10^5)(1.3*10^6) + (7.1*10^5)(v3) = 1.2*10^13 (1.2*10^13) - (9.66*10^11+1.079*10^12) = (7.1 *10^5)(v3) 9.955*10^12 = (7.1 *10^5)(v3) (v3) = 1.4*10^7 :( I...

Homework Statement A spaceship of mass 2.00×10^6 kg is cruising at a speed of 6.00×10^6 m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 4.60×10^5 kg, is blown straight backward with a speed of 2.10×10^6 m/s. A second piece, with mass...