Recent content by tzimie

So what you are saying is that the difference is explained by the rotation. I had almost agreed with you until I found a contradicting scenario Imagine 2 non-rotating neutron star collision 'head-on', like billard balls, so the resulting neutron star has no rotation. Obviously, the amount of...

1. If the number of neutrons is the same, the final state will be the same 2. Effects of rotation are minor 3. Different merger scenarios result in different quadripole moment, so different amount if mass is radiated away I beileve these 3 items are mutually inconsistent, at least one should be...

You can say, ok, may be the number of neutrons is not conserved during violent merger. But let's keep GR but replace the Standard Model with an alternative physics, where there is only one fermion, "pokemon" instead of neutron, and "pokemonness" is strictly conserved, so the number of particles...

Thank you both. You helped me a lot. Let me ask related question. Two one-solar mass neutron stars merge. Due to different initial conditions, different amount of mass in radiated away, so say remnants are 1.8Msun and 1.9Msun for 2 different scenarios But wait, in both cases the number of...

Hi I have two black holes 1 Sun mass each, when they merge a significant percentage of the mass is lost and is radiated away, so the combined black hole remnant is only, say, 1.8M. What is a behavior of the test body on an orbit far away from that binary? I assume that after some time...

https://arxiv.org/pdf/astro-ph/0212429.pdf

Yesterday I learned that there may be ergospeheres around neutron stars too. Wow.

I believe if would start to disintegrate - atom on a surface moves down - is pulled to the left very hard - escapes from surface. This is just one of many effects.

I am interested in a case when a chain approaches infinitely the ergosphere, but is not touching it. Lets looks at a sequence of hovering points above and below the ergosphere. Below the ergosphere their path is spacelike and is physically impossible. Above the ergosophere it is timelike...

Peter, I read all your posts very carefully, and of course, I meant the chain completely ABOVE the ergosphere.

You can just define a pre-existing chain around the eternal black hole For example, schwarzschild solution itself is an idealization about the "eternally existing" black hole.

You can move it INFINITELY SLOWLY - it is just a thought experiment anyway. But I have another question, what's about a realistic static chain in a frame-dragging environment? Even if it is not moving, metal contains atoms moving in all directions. I suspect that a rigid body would try to...

obviously, if a SHORT chain is EXACTLY vertical than a chain of ANY length is vertical.

in that case continuity is restored, but the chain is no longer vertical as it approaches the ergosphere. (and yes, I am aware that the notion of "force" is not valid in GR)

The problem with it as I see that the solution is not continuous. The chain is under vertical stress, as it attracts to the black hole, but that stress is not infinite as we are still far above the event horizon (I am aware that the concept of 'force' is not accurate in GR). So when we slowly...