Recent content by Undeterred247

Oh my- Thank you!

26.6m/s = v0 36.5º = θ g = 9.81m/s^2 A) Find Range: (v0^2)/g *sin2θ = (26.6^2)/9.81 * sin2(36.5) = 89.99 I double-checked with the other Range equation (2v0*cosθ * (v0sinθ)/g) so I know I'm doing something wrong. Please help! Thank you edit: A) Correct answer is 69.0

Thank you for your help! I figured it out! The answer is t = 0.572s

I calculated Vy = Voy +ay *t Vy = 0 -981 * (0.286)^2 Vy = -80.24 Then took the total distance 60cm/-80.24 = t = -0.748 But when checked this answer is incorrect.

Thank you! How would I use this time from M to N to calculate for the time from L to N?

Vertical position (x component): y(t) = y0 +v0 * t -1/2*g*t^2 Position yx(t) = 0cm = 40cm + 0 *t -1/2 * 981cm/s/s * t^2 edit: I replaced v0 = 0 and got t = 0.286s, which is incorrect according to the submission. This didn't work so I thought maybe by finding the angle of the throw would help...

Physics Forums found me actually! I needed some help understanding a problem and in the midst of search it showed up! I started searching for more time solution-related problems and here I am!