Recent content by vaibhav garg

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    Polar Coordinates: Position of Particle at T/8

    that is the problem I have been having, I can't figure out as to why I am not getting the correct angular component
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    Polar Coordinates: Position of Particle at T/8

    Is this wrong ?
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    Polar Coordinates: Position of Particle at T/8

    I calculated the polar equation to be r = √(a2cos2(wt) + b2sin2(wt)) r^ and then I differentiated it to get the velocity as v = ((b2 - a2)sin(wt)cos(wt)w)/√(a2cos2(wt) + b2sin2(wt)) r^ + √(a2cos2(wt) + b2sin2(wt))w θ^
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    Polar Coordinates: Position of Particle at T/8

    The angle does not match. tanθ = b/a√2 is given Also this is one of the part of the question, and I still can't understand how to wite the polar equation for this curve
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    Polar Coordinates: Position of Particle at T/8

    1. The question The position of a particle is given by r(t) = acos(wt) i + bsin(wt) j. Assume a and b are both positive and a > b. The plane polar coordinates of a particle at a time t equal to 1/8 of the time period T will be given by _ Homework Equations r(t) = acos(wt) i + bsin(wt) j. The...
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    Understanding the Dynamics of Acceleration in the Wedge Problem

    the horizontal component would be (a-acosα) which is equal to 2asin2α/2 the vertical component 2asin(α/2)cos(α/2) the resultant would be 2asin(α/2)... I am sorry :P but this doesn't matches any of the options
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    Understanding the Dynamics of Acceleration in the Wedge Problem

    that they are both equal. so when we add the the two components it would give the answer to be B. Thanks ehlid :)
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    Understanding the Dynamics of Acceleration in the Wedge Problem

    ok I get what you are saying, so if we take A to be the acceleration of the block wrt to M. therefore it's acceleration with respect to the ground will be (a - Acosα) horizontally and Asinα vertically. But now how do I find a relation between A and a
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    Understanding the Dynamics of Acceleration in the Wedge Problem

    In the adjoining figure if acceleration of M with respect to ground is a, then A) Acceleration of m with respect to M is a B) Acceleration of m with respect to ground is asin(α/2) C) Acceleration of m with respect to ground is a D) Acceleration of m with respect to ground is atan(α) The 2nd...
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    Rotational Mechanics: Incorrect Statements on Motion of Ball

    Now, I get it. Thanks
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    Rotational Mechanics: Incorrect Statements on Motion of Ball

    but wouldn't the grove be applying the normal force in just the perpendicular direction ?
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    Rotational Mechanics: Incorrect Statements on Motion of Ball

    I can't think of anything...
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    Rotational Mechanics: Incorrect Statements on Motion of Ball

    The centrefugal force ?
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    Rotational Mechanics: Incorrect Statements on Motion of Ball

    also 3 would be wrong anyway because if it moved the radius wold be varying.
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    Rotational Mechanics: Incorrect Statements on Motion of Ball

    I don't know but then again what agent would be there for it to move radially outwards.