Recent content by veitch

You're right.. it should be 0= x^2 -.06x -.0009 Which has roots of 0.072 and -0.012 ... But .05 + 2(.072) = 0.194 yet it should equal .0546 atm :(

Homework Statement CH4 (g) + H2O (g) <- -> CO (g) + 3 H2 (g) .2 M CH4 and .2 M H2O are added to an empty 4 L sealed vessel at 1400 K. When equilibrium is established, the concentration of H2 is .444 M. Calculate Kc... which I did and got 4.8 which is the given answer. The real problem I...

Homework Statement For the reaction 2HI (g) <-- --> H2 (g) + I2 (g) Kp = .02 at 445 degrees C Parital pressures are .05, .01 and .01 respectively. Perform a calc to see which way it goes then figure out the equilibrium partial pressures of the gasses The Attempt at a Solution...

Homework Statement Given a sealed vessel at 2000K, initially contains I2 (g) + Cl2 (g) <- -> 2 ICl (g) with partial pressures .3 atm, .3 atm and .5 atm respectively. At equilibrium the partial pressure of ICl has increased by 52.8% (so .764 atm)... calculate Kp. But that is one part that...

Okay, that makes more sense... W=2 x pi x freq thus v(t) = -(2 pi 14)(14.5)Sin[(2 pi 14)(0.82)] which gives -160 cm/s (with 3 sig figs)... but it still isn't right. I suppose there shouldn't be a negative should there? Since speed is scalar... but 160 isn't the right answer either. :/

Homework Statement The position of a mass that is oscillating on a spring is given by x(t) = (14.5cm)cos[(14.0s-1)t]. What is the speed of the mass when t = 0.820 s? Homework Equations A= Amplitude W= Angular frequency x(t) = ACos(Wt) v(t) = -WASin(Wt) The Attempt at a...

I thought I had this stuff figured out, but my answer is wrong. Any tips? Thanks Homework Statement A sign hangs precariously from your prof's office door. Calculate the magnitude of the tension in string 1 if theta-1 = 26.10degrees, theta-2 = 54.87degrees, and the mass of the sign is...