Recent content by vel

I have redrawn my diagram, but we've only done this sort of problem mathematically in class--I have no idea where the nodes should go, not even half-decent guesses. It's why I was trying to find the frequency and wavelength.

I have no scale information given, sadly, but they're two different overtones. The first half of the problem was an open pipe, and I managed that fine, but what I've tried for this has been wrong. I don't have access to the question itself right now (the site crashed on me) but I have my work...

Yes

No, I mean I see all the code as plain text instead of it formatting. It's not that I couldn't type it on my phone, it's that I see the code itself, and it doesn't format at all. I'd like to be able to see my equations. Even your code for LaTeX shows up: I see exactly what you typed (the #...

I read through it, but I'm more often than not on my phone (especially for drawings/diagrams), so using LaTeX would mean I couldn't see my own equations properly. I can space them out more, though

(4 / 3) * (1.8) = 2.4 = lambda 1st overtone: 2.4 / 4 = .6; (2.4 * 3) / 4 = 1.8

So my final would be 2.66(-9.8)(-.0274) = .7155 ? (I've got about ten minutes left to put this in; working full days and needing sleep doesn't help me solve problems, lol)

OP': 1.45cos(11.9) = 1.42 OQ': 1.45cos(4.1) = 1.45 OP' - OQ': 1.42 - 1.45 = -.003

PP': sin(11.9) = opposite (PP')/1.45 -> 1.45sin(11.9) = .298 QQ': 1.45sin(4.1) = .103 .298 + .103 = 4.01

I think we posted at the same time, lmao. I have the sine equations in #28. If I did it that all correctly and my line of thought is right, it should be PEgrav = 2.66(-9.8)(.401) = -10.45

this would be a sine problem, so I went ahead and did that. See any issues there (or with the diagram?)?

I didn't even realize I had it on an angle, lol.

The very bottom one? that one doesn't have a circle, it's one I sent earlier (#20)

More like these, then?