Recent content by Vicinity24

Okay so turns out since it's a strong acid you need to do: pH=pKa+log((moles base - moles acid)/(moles acid)) But you get zero leading to 9.10 for my case. Not sure why it's like this it didn't show the answer either, probably because it's the last assignment of the semester. But anyways...

My answer was 9.10, it doesn't mark it without two decimal places anyways. I'll get the answer with no explanation. I will report back. I

Only given the one pKa I am afraid.

I've got one try left and it doesn't show me the correct answer until after it's due which is a week.

Is it possible that I have to multiple the amount of base by 3 because we're given this picture:

Strange, well thanks for the help.

Using a ratio of one, it's still incorrect though. You don't need to know the 5% approximation for this question as there were a bunch of others where I didn't use it. Also the last thing you said goes beyond what I know right now as this is an introductory chem course in university.

Homework Statement Determine the pH of the solution (to 2 decimal points) after the addition of 50.0 mL of 2.5 M nitric acid (HNO3) to 500 mL of 0.500 M BIS−TRIS propane (C11H26N2O6), a weak base). Assume that the 5% approximation is valid and that the volumes are additive. The pKa of BIS−TRIS...

I forgot to reply when I saw it as I was busy but that really helped. It's really cool how you just made that and tested it. Thanks again! I've gotten better at trusses since then too :P

Alright I got it, thanks JBA and insightful!

Aha At first I was still confused then I realized that member 3 would be in tension since the arrows of both 1 and 4 point to the left. Would 7 be compression then? Since it has one y component over the axis pointing down (6) and two (9 and 7) below, the ones below have to point to the joint to...

For the second one if the top horizontal member is in compression then the interior diagonals are in tension, I was about to ask how you determined the top to be horizontal but then I figured out that to balance the y forces from A, the diagonal has to be in tension. In the third one, the top...

Homework Statement Is this correct? The sum of the forces in the Y have to be zero and there is only two y-components so it's pretty simple to determine this. There are also only two x-components so those will also cancel each other out as they have to go in opposite directions to balance as...

Yes, that was indeed the answer! (Ax=3F, Ay=F) The next part of the question asks for B, which was also correct! (Bx=3F, By=0) Thanks for the help Phantom and Steam!

Then id say Ay is F. So would I say B is 0?