Recent content by walnuts

I turned it in earlier, here's what I did. I'm known for just making stuff up, so correct me if I'm wrong. stress/strain=(F/A)/(delta L/ L) delta L/L=2 and since the volume didn't change A=.5A so, 2*stress/(strain*.5)=mg 4*stress/(strain*g)=m

Homework Statement A spider is caught in the midpoint of a spider thread. The thread breaks under a stress of 8.2E8 N/m^2 and a strain of 2.00. Initially, it was horizontal and had a length of 2.00 cm and a cross-sectional area of 8.E-12 m^2. As the thread was stretched under the weight of...