Recent content by wat2000

Thanks I appreciate the help.

Now I am getting x= -7. The way i got that answer is like this. first i subtracted 4 from both sides. this gave me -log(3-x)=-1. Then i divided both sides by -1. This gave me log(3-x)=1. I am not really sure what this next step is but its what they did in the book. It just looks like they took...

4-log(3-x)=3 i got -10/3. is this correct? and if it isn't can someone show me the steps?

If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?

no 9-(1/3) raised to the n-3.

So would it be 3+1+1+1+1/3+1/3+1/3?

so am I subtracting every time the ball bounces?

I get 14.97 for y and 8350 for x. do i subtract 1497 from 8350 to get the depth?

so would that give me my depth?so the focus would be 64/7 and the depth would be 14.97. and if so, what is the 8350 i got from multiplying 167 and 50?

wouldnt solving for x give me x= 2500/167?

its 50 right? If so does that make the depth 50?

could i do (1/67)x^2 with x=50 and square x and get 2500/167?

so y = 50 ft? where do i go from there?

If a particular radio telescope is 100ft in diameter and has a cross section modeled by the equation x^2=167y, how deep is the parabolic dish? What is the location of the focus? can someone show me some steps to solving this? I have (167/4,0) as the focus for the second part but I am not...

so a would equal 2/7? Do i solve 2a=7 to create that fraction?