Simplifying Ellipses: Solving for b^2 = (5/3)

wat2000 · Apr 24, 2011

If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?

LCKurtz · Apr 24, 2011

wat2000 said:

If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?

[tex]\pm \sqrt{\frac 5 3} = \pm \frac{\sqrt{15}} 3[/tex]

Simplifying Ellipses: Solving for b^2 = (5/3)

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Simplifying Ellipses: Solving for b^2 = (5/3)

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