wat2000
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If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?
Simplifying Ellipses: Solving for b^2 = (5/3)
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wat2000 said:If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?
[tex]\pm \sqrt{\frac 5 3} = \pm \frac{\sqrt{15}} 3[/tex]
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