Simplifying Ellipses: Solving for b^2 = (5/3)

[wat2000]

If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?

 

[LCKurtz]

If I was solving an ellipse problem and I had b^2 = (5/3) wouldn't that be simplified to + or - sqrt (15/3)? Or would it just be + or - sqrt (5/3)?

$$\pm \sqrt{\frac 5 3} = \pm \frac{\sqrt{15}} 3$$