Recent content by Wooh

You can make an equation for the area of a given slice of the pyradmid with respect to the height (since the height will determine the side length, which will of course influence the area since it is equilateral..I believe it's ((a)^(3/2))/4 but I forget.

Your reasoning is correct.

Hah, Leon...I'm originally from Dallas (studying out of state). I wouldn't put it quite as bluntly as you did, but basically, if you can hack a 4 year college, community college probably will not challenge you as much. It's not to impugn the quality of education there...just to say that it'd be...

On a slightly related note! There is a theorem that applies that is quite handy, called Green's Theorem (I wholeheartedly recommend looking it up) Basically, if dQ/dx does not equal dP/dy (meaning the integral isn't exact), then the integral is equal to the double integral over the bounded...

I am currently a business/CS major at the University of Pennsylvania, and am trying to make the (very painful) switch out of the business school and into the liberal arts program to study math (I know, I know...UPenn is reknowned for math, but whatever, good enough for me). Here's my...

Howdy all! I am a freshman studying Business, Computer Science, and Mathematics (the first is so much lamer than the latter two ;)). I wanted to beef up my knowledge, and I was wondering if you guys could recommend books in these two areas: Transcendental numbers and their ilk, how it was...

It was a problem my calc teacher gave me to work out. Work will be forthcoming. It is just hard to get work onto the internet, which is why I was hoping someone could at least criticize the 2/3 value. thanks though.

It's not homework. I am doing an extra problem for fun. Can you at least let me know if 2/3 is correct? I just don't want to be chasin' waterfalls...

Bump? I would really like a little direction :X

ah, well, there I go. Thanks! Hmm, I am going to have to try and apply that to the other one. Can you take a look at the other one too?

And additionally, I have no idea how to simply integrate (for a circle of, let's say radius 2) \int _{-1} ^{1} \sqrt{4-x^2} dx Edit: well, I can "integrate it" with a really ugly sector+triangle thing, but I hope there is a better way...I don't want to have to do with once with a...

As far as my screen, it seems to have attached ok... But basically it is 2\int_{-.5} ^{.5} (\int_{-\sqrt{.25-y^2}} ^{\sqrt{.25-y^2} }\sqrt{.25-x^2}dx)dy That is for the second problem.

the sum of 8 consecutive numbers can be written as such: (n+n+7)8/2 following the whole (n1+nfinal)(total/2) form. Using this, we get that (n+n+7)4/8=x or 2x=2n+7, meaning that n=(2x-7)2

aaanyone have an idea?

Hmm, is there an easy way to evaluate this integral: 2*integral(sqrt[.25-x^2],-y,y). Basically, I want to know how to find the area as depicted by the attached image (untitled) as a function. This goes along with a problem that I am trying to solve. If you know how to do it or something...